Lemma 3.1.
Let
be a uniformly convex Banach space with the convex modulus of power type
,
a nonempty closed convex subset of
satisfying
, and
hemicontractive mappings with
. Let
,
,
,
and
be the sequences in (II) and
where
is the constant in Remark 2.4. Then,
(1)
exists for all
,
(2)
exists,
-
(3)
if
is continuous, then
, for all
.
Proof. (1) Let
. By the boundedness assumption on
, there exists a constant
, for any
, such that
. From the definition of hemicontractive mappings, we have
Using Lemmas 2.3, 2.5, and (3.2), we obtain
Hence,
It follows from (II) and Lemma 2.5 that
By the condition
, we may assume that
Therefore,
Substituting (3.7) into (3.4), we get
Assumptions (i) and (ii) imply that there exists a positive integer
such that for every
,
Hence, for all
,
where
From (3.9) and conditions (i) and (ii), it follows that
By Lemma 2.6, we see that
exists and the sequence
is bounded.
(2) It is easy to verify that
exists.
(3) By the boundedness of
, there exists a constant
such that
, for all
. From (3.10), we get, for
,
which implies
Thus,
It implies that
Therefore, by (3.7), we have
Using (II), we obtain
By a combination with the continuity of
(
, we get
It is clear that for each
, there exists
such that
. Consequently,
This completes the proof.
Theorem 3.2.
Let the assumptions of Lemma 3.1 hold, and let
be continuous. Then,
converges strongly to a common fixed point of
if and only if
.
Proof.
The necessity is obvious.
Now, we prove the sufficiency. Since
, it follows from Lemma 3.1 that
.
For any
, we have
Hence, we get
So,
is a Cauchy sequence in
. By the closedness of
, we get that the sequence
converges strongly to
. Let a sequence
, for some
, be such that
converges strongly to
. By the continuity of
, we obtain
Therefore,
. This implies that
is closed. Therefore,
is closed. By
, we get
. This completes the proof.
Theorem 3.3.
Let the assumptions of Lemma 3.1 hold. Let
be continuous and
satisfy condition
. Then,
converges strongly to a common fixed point of
.
Proof.
Since
satisfies condition
, and
for each
, it follows from the existence of
that
. Applying the similar arguments as in the proof of Theorem 3.2, we conclude that
converges strongly to a common fixed point of
. This completes the proof.
As a direct consequence of Theorem 3.3, we get the following result.
Corollary 3.4 (see [12, Theorem 3]).
Let H be a real Hilbert space,
a nonempty closed convex subset of
satisfying
, and
continuous hemicontractive mapping which satisfies condition (A). Let
be a real sequence in
with
. For any
, the sequence
is defined by
Then,
converges strongly to a fixed point of
.
Proof.
Employing the similar proof method of Lemma 3.1, we obtain by (3.10)
This implies
By
, we have
. Equation (3.7) implies that 
. Since
satisfies condition (A) and the limit
exists, we get
. The rest of the proof follows now directly from Theorem 3.2. This completes the proof.
Remark 3.5.
Theorems 3.2 and 3.3 extend [12, Theorem 3] essentially since the following hold.
-
(i)
Hilbert spaces are extended to uniformly convex Banach spaces.
-
(ii)
The requirement of compactness on domain
on [12, Theorem 3] is dropped.
-
(iii)
A single mapping is replaced by a family of mappings.
-
(iv)
The Mann-type implicit iteration is replaced by the generalized Mann iteration. So the restrictions of
with
for some
are relaxed to
. The error term is also considered in the iteration (II).
Moreover, if
, then
is well defined by (II). Hence, Theorems 3.2 and 3.3 are also answers to the question proposed by Qing [13].
Theorem 3.6.
Let
and
be as the assumptions of Lemma 3.1. Let
be strictly pseudocontractive mappings with
being nonempty. Let
,
,
,
, and
be the sequences in (II) and
where
is the constant in Remark 2.4. Then,
(1)
converges strongly to a common fixed point of
if and only if
.
-
(2)
If
satisfies condition (
) , then
converges strongly to a common fixed point of
.
Remark 3.7.
Theorem 3.6 extends the corresponding result [6, Theorem 3.1].