We begin this section by proving a strong convergence theorem of an implicit iterative sequence
obtained by the viscosity approximation method for finding a common element of the set of solutions of the variational inclusion, the set of solutions of an equilibrium problem and the set of fixed points of a nonexpansive mapping.
Throughout the rest of this paper, we always assume that
is a contraction of
into itself with coefficient
, and
is a strongly positive bounded linear operator with coefficient
and
. Let
be a nonexpansive mapping of
into
. Let
be an
-inverse-strongly monotone mapping,
be a maximal monotone mapping and let
be defined as in (2.10). Let
be a sequence of mappings defined as Lemma 2.1. Consider a sequence of mappings
on
defined by
where
By Lemma 2.2, we note that
is a contraction. Therefore, by the Banach contraction principle,
has a unique fixed point
such that
Theorem 3.1.
Let
be a real Hilbert space, let
be a bifunction from
satisfying (A1)–(A4) and let
be a nonexpansive mapping on
. Let
be an
-inverse-strongly monotone mapping,
be a maximal monotone mapping such that
Let
be a contraction of
into itself with a constant
and let
be a strongly bounded linear operator on
with coefficient
and
. Let
,
and
be sequences generated by
and
where
,
and
satisfy
and
. Then,
,
and
converges strongly to a point
in
which solves the variational inequality:
Equivalently, we have 
Proof.
First, we assume that
. By Lemma 2.2, we obtain
. Let
Since
we have
We note from
that
. As
is nonexpansive, we have
for all
Thus, we have
It follows that
Hence
is bounded and we also obtain that
,
,
,
and
are bounded. Next, we show that
. Since
, we note that
Moreover, it follows from Lemma 2.1 that
and hence
Therefore, we have
and hence
Since
is bounded and
it follows that
as 
Put
. From (3.10), it follows by the nonexpansive of
and the inverse strongly monotonicity of
that
which implies that
Since
, we have
as
. Since
is
–inverse-strongly monotone and
is nonexpansive, we have
Thus, we have
From (3.5), (3.10), and (3.15), we have
Thus, we get
Since
,
as
, we have
as
. It follows from the inequality
that
as
. Moreover, we have
as
.
Put
. Since both
and
are nonexpansive, we have
is a nonexpansive mapping on
and then we have
for all
. It follows by Theorem 3.1 of Plubtieng and Punpaeng [6] that
converges strongly to
, where
and
, for all
. We will show that
. Since
converges strongly to
, we also have
. Let us show
Assume
Since
and
, we have
Since
it follows by the Opial's condition that
This is a contradiction. Hence
We now show that
. In fact, since
is
–inverse-strongly monotone,
is an
-Lipschitz continuous monotone mapping and
. It follows from Lemma 2.4 that
is maximal monotone. Let
, that is,
. Again since
, we have
that is,
By the maximal monotonicity of
, we have
and so
It follows from
,
and
that
Since
is maximal monotone, this implies that
that is,
. Hence,
. Since
, we have
. It implies that
is the unique solution of the variational inequality (3.4).
Now we prove the following theorem which is the main result of this paper.
Theorem 3.2.
Let
be a real Hilbert space, let
be a bifunction from
satisfying (A1)–(A4) and let
be a sequence of nonexpansive mappings on
. Let
be an
-inverse-strongly monotone mapping,
be a maximal monotone mapping such that
Let
be a contraction of
into itself with a constant
and let
be a strongly bounded linear operator on
with coefficient
and
. Let
,
and
be sequences generated by
and
for all
, where
,
and
satisfy
Suppose that
for any bounded subset
of
. Let
be a mapping of
into itself defined by
and suppose that
. Then,
,
and
converges strongly to
, where
is a unique solution of the variational inequalities (3.4).
Proof.
Since
, we may assume that
for all
. First we will prove that
is bonded. Let
Then, we have
It follows from (3.25) and induction that
Hence
is bounded and therefore
,
and
are also bounded. Next, we show that
. Since
is nonexpansive, it follows that
Then, we have
where
. On the other hand, we note that
Putting
in (3.29) and
in (3.30),
and
By (A2), we have
and hence
Since
we assume that there exists a real number
such that
for all
Thus, we have
and hence
where
. From (3.28), we have
Since
is bounded, it follows that
. Hence, by Lemma 2.3, we have
as
. From (3.34) and
, we have
. Moreover, we have from (3.27) that
.
We note from (3.23) that
. Then, we have
Since
,
and
, we get
. From the proof of Theorem 3.1, we have
for all
. Therefore, we have
and hence
Since
is bounded,
and
, it follows that
as 
Put
. It follows from (3.38), the nonexpansive of
and the inverse strongly monotonicity of
that
This implies that
Since
and
, we have
as
.From (3.5), (3.15) and (3.38), we have
Thus, we obtain
Since
,
and
, we have
as
. It follows from the inequality
that
as
. Moreover, we note that
as
. Since
for all
, it follows that
. Next, we show that
where
is a unique solution of the variational inequality (3.4). To show this inequality, we choose a subsequence
of
such that
Since
is bounded, there exists a subsequence
of
which converges weakly to
. Without loss of generality, we can assume that
From
we obtain
. Let us show
. It follows by (3.23) and (A2) that
and hence
Since
and
it follows by (A4) that
for all
For
with
and
let
Since
and
we have
and hence
So, from (A1) and (A4) we have
and hence
. From (A3), we have
for all
and hence
By the same argument as in proof of Theorem 3.1, we have
and hence
. This implies that
Finally we prove that
. From (3.23), we have
This implies that
where
and
. It easily verified that
,
and
. Hence, by Lemma 2.1, the sequence
converges strongly to
.
As in [10, Theorem 4.1], we can generate a sequence
of nonexpansive mappings satisfying condition
. for any bounded
of
by using convex combination of a general sequence
of nonexpansive mappings with a common fixed point.
Corollary 3.3.
Let
be a real Hilbert space, let
be a bifunction from
satisfying (A1)–(A4) and let
be an
-inverse-strongly monotone mapping,
be a maximal monotone mapping. Let
be a contraction of
into itself with a constant
and let
be a strongly bounded linear operator on
with coefficient
and
. Let
be a family of nonnegative numbers with indices
with
such that
(i)
(ii)
(iii)
Let
be a sequence of nonexpansive mappings on
with
and let
,
and
be sequences generated by
and
for all
, where
,
and
satisfy
Then,
,
and
converges strongly to
in
which solves the variational inequality:
If
and
in Theorem 3.2, we obtain the following corollary.
Corollary 3.4 (see Peng et al. [9]).
Let
be a real Hilbert space, let
be a bifunction from
satisfying (A1)–(A4) and let
be a nonexpansive mapping on
. Let
be an
-inverse-strongly monotone mapping,
be a maximal monotone mapping such that
Let
be a contraction of
into itself with a constant
. Let
,
and
be sequences generated by
and
for all
, where
,
and
satisfy
Then,
,
and
converges strongly to
, where
.
If
and
in Theorem 3.2, we obtain the following corollary.
Corollary 3.5 (see S. Plubtieng and R. Punpaeng [6]).
Let
be a real Hilbert space, let
be a bifunction from
satisfying (A1)–(A4) and let
be a nonexpansive mapping on
such that
Let
be a contraction of
into itself with a constant
and let
be a strongly bounded linear operator on
with coefficient
and
. Let
,
and be sequences generated by
and
for all
, where
and
satisfy
Then,
and
converges strongly to a point
in
which solves the variational inequality: