Let
be a real Hilbert space,
be a lower semicontinuous and convex real-valued function,
be an equilibrium bifunction. Let
be a mapping and
be a mapping. In this section, we first introduce the following new iterative algorithm.
Algorithm 3.1.
Let
be a positive parameter. Let
be a sequence in
and
be a sequence in
. Define the sequences
,
and
by the following manner:
Now we give a strong convergence result concerning Algorithm 3.1 as follows.
Theorem 3.2.
Let
be a real Hilbert space. Let
be a lower semicontinuous and convex functional. Let
be an equilibrium bifunction satisfying conditions (H1)–(H3). Let
be an
-Lipschitz continuous and
-strongly monotone mapping and
be a demiclosed and
-demicontractive mapping such that
. Assume what follows.
(i)
is Lipschitz continuous with constant
such that
(a)
,
(b)
is affine in the first variable,
(c)for each fixed
,
is sequentially continuous from the weak topology to the weak topology.
(ii)
is
-strongly convex with constant
and its derivative
is not only sequentially continuous from the weak topology to the strong topology but also Lipschitz continuous with constant
such that
.
(iii)For each
; there exist a bounded subset
and
such that, for any
,
(iv)
for some
,
and
.
Then the sequences
,
, and
generated by (3.1) converge strongly to
which solves the problem (2.8) provided
is firmly nonexpansive.
Proof.
First, we prove that
,
, and
are all bounded. Without loss of generality, we may assume that
. Given
and
, we have
that is,
Take
. From (3.1), we have
Therefore,
where
.
Note that
and
are firmly nonexpansive. Hence, we have
which implies that
From (2.2) and (3.1), we have
From (3.6)–(3.9), we have
This implies that
is bounded, so are
and
.
From (3.1), we can write
. Thus, from (3.9), we have
Since
,
. Therefore, from (3.8) and (3.11), we obtain
We note that
and
are bounded. So there exists a constant
such that
Consequently, we get
Now we divide two cases to prove that
converges strongly to
.
Case 1.
Assume that the sequence
is a monotone sequence. Then
is convergent. Setting
.
(i)If
, then the desired conclusion is obtained.
(ii)Assume that
. Clearly, we have
this together with
and (3.14) implies that
that is to say
Let
be a weak limit point of
. Then there exists a subsequence of
, still denoted by
which weakly converges to
. Noting that
, we also have
Combining (3.1) and (3.17), we have
Since
is demiclosed, then we obtain
.
Next we show that
. Since
, we derive
From the monotonicity of
, we have
and hence
Since
and
weakly, from the weak lower semicontinuity of
and
in the second variable
, we have
for all
. For
and
, let
. Since
and
, we have
and hence
. From the convexity of equilibrium bifunction
in the second variable
, we have
and hence
. Then, we have
for all
and hence
.
Therefore, we have
Thus, if
is a solution of problem (2.8), we have
Suppose that there exists another subsequence
which weakly converges to
. It is easily checked that
and
Therefor, we have
Since
is
-strongly monotone, we have
By (3.17)–(3.30), we get
From (3.12), for
, we deduce that there exists a positive integer number
large enough, when
,
This implies that
Since
and
is bounded, hence the last inequality is a contraction. Therefore,
, that is to say,
.
Case 2.
Assume that
is not a monotone sequence. Set
and let
be a mapping for all
by
Clearly,
is a nondecreasing sequence such that
as
and
for
. From (3.14), we have
thus
Therefore,
Since
, for all
, from (3.12), we get
which implies that
Since
is bounded, there exists a subsequence of
, still denoted by
which converges weakly to
. It is easily checked that
. Furthermore, we observe that
Hence, for all
,
Therefore
which implies that
Thus,
It is immediate that
Furthermore, for
, it is easily observed that
if
(i.e.,
), because
for
. As a consequence, we obtain for all
,
Hence
, that is,
converges strongly to
. Consequently, it easy to prove that
and
converge strongly to
. This completes the proof.
Remark 3.3.
The advantages of these results in this paper are that less restrictions on the parameters
are imposed.
As direct consequence of Theorem 3.2, we obtain the following.
Corollary 3.4.
Let
be a real Hilbert space. Let
be a lower semicontinuous and convex functional. Let
be an equilibrium bifunction satisfying conditions (H1)–(H3). Let
be an
-Lipschitz continuous and
-strongly monotone mapping and
be a nonexpansive mapping such that
. Assume what follows.
(i)
is Lipschitz continuous with constant
such that;
(a)
,
(b)
is affine in the first variable,
(c)for each fixed
,
is sequentially continuous from the weak topology to the weak topology.
(ii)
is
-strongly convex with constant
and its derivative
is not only sequentially continuous from the weak topology to the strong topology but also Lipschitz continuous with constant
such that
.
(iii)For each
; there exist a bounded subset
and
such that, for any
,
(iv)
for some
,
and
.
Then the sequences
,
, and
generated by (3.1) converge strongly to
which solves the problem (2.8) provided
is firmly nonexpansive.
Corollary 3.5.
Let
be a real Hilbert space. Let
be a lower semicontinuous and convex functional. Let
be an equilibrium bifunction satisfying conditions (H1)–(H3). Let
be an
-Lipschitz continuous and
-strongly monotone mapping and
be a strictly pseudo-contractive mapping such that
. Assume what follows.
(i)
is Lipschitz continuous with constant
such that
(a)
,
(b)
is affine in the first variable,
(c)for each fixed
,
is sequentially continuous from the weak topology to the weak topology.
(ii)
is
-strongly convex with constant
and its derivative
is not only sequentially continuous from the weak topology to the strong topology but also Lipschitz continuous with constant
such that
.
(iii)For each
; there exist a bounded subset
and
such that, for any
,
(iv)
for some
,
and
.
Then the sequences
,
and
generated by (3.1) converge strongly to
which solves the problem (2.8) provided
is firmly nonexpansive.