Throughout this paper, a Banach space
will always be over the real scalar field. We denote its norm by
and its dual space by
. The value of
at
is denoted by
and the normalized duality mapping
from
into
is defined by
Let
denote the set of all fixed points for a mapping
, that is,
, and let
denote the set of all positive integers. We write
(resp.
) to indicate that the sequence
weakly (resp. wea
) converges to
; as usual
will symbolize strong convergence.
In the proof of our main results, we need the following definitions and results. Let
denote the unit sphere of a Banach space
.
is said to have (i) a Gâteaux differentiable norm (we also say that
is smooth), if the limit
exists for each
; (ii) a uniformly Gâteaux differentiable norm, if for each
in
, the limit (2.2) is uniformly attained for
; (iii) a Fréchet differentiable norm, if for each
, the limit (2.2) is attained uniformly for
; (iv) a uniformly Fréchet differentiable norm (we also say that
is uniformly smooth), if the limit (2.2) is attained uniformly for
. A Banach space
is said to be (v) strictly convex if
(vi) uniformly convex if for all
,
such that
For more details on geometry of Banach spaces, see [21, 22].
If
is a nonempty convex subset of a Banach space
and
is a nonempty subset of
, then a mapping
is called a retraction if
is continuous with
. A mapping
is called sunny if
whenever
and
. A subset
of
is said to be a sunny nonexpansive retract of
if there exists a sunny nonexpansive retraction of
onto
. We note that if
is closed and convex of a Hilbert space
, then the metric projection coincides with the sunny nonexpansive retraction from
onto
. The following lemma is well known which is given in [22, 23].
Lemma 2.1 (see [22, Lemma 5.1.6]).
Let
be nonempty convex subset of a smooth Banach space
,
,
the normalized duality mapping of
, and
a retraction. Then
is both sunny and nonexpansive if and only if there holds the inequality:
Hence, there is at most one sunny nonexpansive retraction from
onto
.
In order to showing our main outcomes, we also need the following results. For completeness, we give a proof.
Proposition 2.2.
Let
be a convex subset of a smooth Banach space
. Let
be a subset of
and let
be the unique sunny nonexpansive retraction from
onto
. Suppose
is a weak contraction with a function
on
and
is a nonexpansive mapping. Then
(i)the composite mapping
is a weak contraction on
;
(ii)For each
, a mapping
is a weak contraction on
. Moreover,
defined by (2.4) is well definition:
(iii)
if and only if
is a unique solution of the following variational inequality:
Proof.
For any
, we have
So,
is a weakly contractive mapping with a function
. For each fixed
and
, we have
Namely,
is a weakly contractive mapping with a function
. Thus, Theorem 1.2 guarantees that
has a unique fixed point
in
, that is,
satisfying (2.4) is uniquely defined for each
. (i) and (ii) are proved.
Subsequently, we show (iii). Indeed, by Theorem 1.2, there exists a unique element
such that
. Such a
fulfils (2.5) by Lemma 2.1. Next we show that the variational inequality (2.5) has a unique solution
. In fact, suppose
is another solution of (2.5). That is,
Adding up gets
Hence
by the property of
. This completes the proof.
Let
be a sequence of nonexpansive mappings with
on a closed convex subset
of a Banach space
and let
be a sequence in
with (C1).
is said to have Browder's property if for each
, a sequence
defined by
for
, converges strongly. Let
be a sequence in
with (C1) and (C2). Then
is said to have Halpern's property if for each
, a sequence
defined by
for
, converges strongly.
We know that if
is a uniformly smooth Banach space or a uniformly convex Banach space with a uniformly Gâteaux differentiable norm,
is bounded,
is a constant sequence
, then
has both Browder's and Halpern's property (see [7, 10, 11, 23], resp.).
Lemma 2.3 (see [24, Proposition 4]).
Let
have Browder's property. For each
, put
, where
is a sequence in
defined by (2.10). Then
is a nonexpansive mapping on
.
Lemma 2.4 (see [24, Proposition 5]).
Let
have Halpern's property. For each
, put
, where
is a sequence in
defined by (2.11). Then the following hold: (i)
does not depend on the initial point
. (ii)
is a nonexpansive mapping on
.
Proposition 2.5.
Let
be a smooth Banach space, and
have Browder's property. Then
is a sunny nonexpansive retract of
, and moreover,
define a sunny nonexpansive retraction from
to
.
Proof.
For each
, it is easy to see from (2.10) that
This implies for any
and some
,
The smoothness of
implies the norm weak
continuity of
[22, Theorems 4.3.1, 4.3.2], so
Thus
By Lemma 2.1,
is a sunny nonexpansive retraction from
to
.
We will use the following facts concerning numerical recursive inequalities (see [25–27]).
Lemma 2.6.
Let
and
be two sequences of nonnegative real numbers, and
a sequence of positive numbers satisfying the conditions
and
. Let the recursive inequality
be given where
is a continuous and strict increasing function for all
with
. Then ( 1)
converges to zero, as
; ( 2) there exists a subsequence
such that