First we extend Zhang and Song's theorem (Theorem 1.4) to the case where one of the mappings is multivalued.
Theorem 4.1.
Let
be a complete metric space and let
and
be two mappings such that for all
,
(i.e., generalized
-weak contractive) where
is l.s.c. with
and
for all
. Then there exists a unique point
such that
.
Proof.
Unicity of the common fixed point follows from (4.1).
Obviously
if and only if
is a common fixed point of
and
.
Let
and
. Let
. By Lemma 2.3, there exists
such that
We let
. Inductively, we let
, and by Lemma 2.3, we choose
such that
We break the argument into four steps.
Step 1.
Proof.
Using (4.1) and (4.3),
where
So
. Hence by (4.4),
Also
where
So
. Hence by (4.7),
Therefore, by (4.6) and (4.9), we conclude that
for all
.
Therefore, the sequence
is monotone nonincreasing and bounded below. So there exists
such that
Since
is l.s.c.,
By (4.4), we conclude that
and so
. Hence
.
Step 2.
is a bounded sequence.
Proof.
If
were unbounded, then by Step 1,
and
are unbounded. We choose the sequence
such that
,
is even and minimal in the sense that
, and
, and similarly
is odd and minimal in the sense that
, and
is even and minimal in the sense that
and
, and
is odd and minimal in the sense that
and
.
Obviously
for every
. By Step 1, there exists
such that for all
we have
. So for every
, we have
and
Hence
Also
and this shows that 
So if
is odd, then
where
and this shows that
Since
is l.s.c. and (4.16) holds, we have
. So
and this is a contradiction.
Step 3.
is Cauchy.
Proof.
Let
. Since
is bounded,
for all
. Obviously
is decreasing. So there exists
such that
. We need to show that
.
For every
, there exists
such that
and
By (4.18), we conclude that
From Step 1 and (4.19), we have
So we may assume that for every
,
is odd and
is even. Hence
where
This inequality shows that
Since
is l.s.c. and (4.21) holds, we have
. Hence
and so
. Therefore,
is a Cauchy sequence.
Step 4.
and
have a common fixed point.
Proof.
Since
is complete and
is Cauchy, there exists
such that
For every
where
and this shows that 
Since
is l.s.c. and (4.23) holds, letting
in (4.23) we get
So
and hence
. Since
, then
.Also
where
So from (4.26), we have
Thus
, and hence
. Therefore,
.
Remark 4.2.
In the proof of Theorem
in Zhang and Song [8], the boundedness of the sequence
is used, but not proved. Also, for the proof that
is a Cauchy sequence, the monotonicity of
is used, without being explicitly mentioned.
In our proof of Theorem 4.1, which is different from [8, Theorem
],
is not assumed to be nondecreasing.
The following theorem extends Rhoades' theorem by assuming
to be only l.s.c..
Theorem 4.3.
Let
be a complete metric space, and let
be a mapping such that
for every
(i.e.,
-weak contractive), where
is an l.s.c. function with
and
for all
. Then
has a unique fixed point.
Proof.
The proof is similar to the proof of Theorem 4.1, by taking
, and replacing
with
.
Remark 4.4.
With a similar proof as in Theorem 4.1, in Theorem 4.3 we can replace the inequality (4.29) by the following inequality (4.30) for two single valued mappings
.