Let F be a k-Lipschitzian and η-strongly monotone operator on H with 0 < k, T : H → H be a nonexpansive mapping. Let t ∈ (0,η/k2) and
, and consider a mapping St on H defined by
It is easy to see that S
t
is a contraction. Indeed, from Lemma 2.5, we have
for all x, y ∈ H. Hence, it has a unique fixed point, denoted as x
t
, which uniquely solves the fixed point equation
Theorem 3.1. Let H be a real Hilbert space. Let T : H → H be a nonexpansive mapping such that F (T ) ≠ ∅,. Let F be a k-Lipschitzian and η-strongly monotone operator on H with 0 < η ≤ k. For each t ∈ (0, η/k2), let the net {x
t
} be generated by (3.1). Then, as t → 0, the net {x
t
} converges strongly to a fixed point x* of T which solves the variational inequality:
Proof. We first show the uniqueness of a solution of the variational inequality (3.2), which is indeed a consequence of the strong monotonicity of F. Suppose x* ∈ F (T ) and
both are solutions to (3.2), then
and
Adding up (3.3) and (3.4) yields
The strong monotonicity of F implies that
and the uniqueness is proved. Later, we use x* ∈ F (T ) to denote the unique solution of (3.2).
Next, we prove that {x
t
} is bounded. Take u ∈ F (T ), from (3.1) and using Lemma 2.5, we have
that is,
Observe that
From t → 0, we may assume, without loss of generality, that
, where is a arbitrarily small positive number. Thus, we have
is continuous,
. Therefore, we obtain
From (3.5) and (3.6), we have that {x
t
} is bounded and so is {Fx
t
}.
On the other hand, from (3.1), we obtain
To prove that x
t
→ x*. For a given u ∈ F (T ), using Lemma 2.5, we have
Therefore,
From
, we have
and
. Observe that, if x
t
⇀ u, we have
.
Since {x
t
} is bounded, we see that if {t
n
} is a sequence in
such that t
n
→ 0 and
, then by (3.8), we see
. Moreover, by (3.7) and using Lemma 2.1, we have
. We next prove that
solves the variational inequality (3.2). From (3.1) and u ∈ F (T ), we have
that is,
Now replacing t in (3.9) with t
n
and letting n → ∞, we have
That is
is a solution of (3.2), hence
by uniqueness. In a nutshell, we have shown that each cluster point of {x
t
} (at t → 0) equals x*. Therefore, x
t
→ x* as t → 0.
Theorem 3.2. Let H be a real Hilbert space. Let F be a k-Lipschitzian and η-strongly monotone operator on H with 0 < η ≤ k. Let
be an infinite family of nonexpansive mappings such that
and W
n
be a W-mapping defined by (2.3). Let {λ
n
} be a sequence in [0, ∞) and {α
n
} be a sequence in [0,1], ε be a arbitrarily small positive number. Assume that the control conditions (C2), (C 1)', and (C 5)' hold for {λ
n
} and {α
n
},
(C 1)':
, ∀n ≥ n0 for some integer n0 ≥ 0, and
(C 5) ': 0 < γ ≤ lim infn→∞α
n
lim supn→∞α
n
< 1 for some γ ∈ (0, 1).
For x0 ∈ H arbitrarily, let the sequence {y
n
} be generated by (1.2). Then,
where
solves the variational inequality
Proof. On the one hand, suppose that λ
n
F(x
n
) → 0(n → ∞). We proceed with the following steps:
Step 1. We claim that {x
n
} is bounded. In fact, let
, from (1.2), (C 1)' and using Lemma 2.5, we have
∀n ≥ n0 for some integer n0 ≥ 0, where
. Then, from (1.2) and (3.10), we obtain
By induction, we have
∀n ≥ n0 for some integer n0 ≥ 0, where
.Therefore, {x
n
} is bounded. We also obtain that {y
n
}, {W
n
y
n
} and {Fx
n
} are bounded.
Step 2. We claim that limn→∞||xn+1- x
n
|| = 0. To this end, define xn+1= (1 - α
n
)x
n
+ α
n
z
n
. We observe that
From (2.3), for
, we have
where M2 = sup{2 ||y
n
- u||, n ≥ 0}. By (1.2) and (3.12), we have
Substituting (3.13) into (3.11), we have
that is,
Observing λ
n
F(x
n
) → 0(n → ∞) and 0 < ξ
i
≤ b < 1, it follows that
By (C 5)' and using Lemma 2.2, we have limn→∞||z
n
- x
n
|| = 0. Therefore,
Step 3. We claim that limn→∞||x
n
- W
n
x
n
|| = 0. Observe that
that is,
Step 4. We claim that limn→∞||x
n
- Wx
n
|| = 0. Indeed, we have
By (3.15), (3.16) and using Lemma 2.6, we obtain
Step 5. We claim that lim supn→∞〈Fx*, x* - x
n
〉 ≤ 0, where x* = limn→∞x
t
and x
t
defined by x
t
= W[(1 - tF)x
t
]. Since x
n
is bounded, there exists a subsequence
of {x
n
} which converges weakly to ω. From Step 4, we obtain
. From Lemma 2.1, we have ω ∈ F(W). Hence, by Theorem 3.1, we have
Step 6. We claim that {x
n
} converges strongly to
. From (1.2), we have
∀n ≥ n0 for some integer n0 ≥ 0, where M3 = 2||Fx*||. For every n ≥ n0, put
and δ
n
= 2M1〈x* - x
n
, Fx*〉 +M1M3 ||λ
n
Fx
n
||. It follows that
It is easy to see that
and lim supn→∞δ
n
≤ 0. Hence, by Lemma 2.3, the sequence {x
n
} converges strongly to
.
Observe that
It follows that the sequence {y
n
} converges strongly to
. From x* = limt→0x
t
and Theorem 3.1, we have x* is the unique solution of the variational inequality: 〈Fx*, x* - u〉 ≤ 0,
.
On the other hand, suppose that
as n → ∞, where
solves the variational inequality:
From (1.2), we have
that is,
. Again from (1.2), we obtain that
Since
and
, we get λ
n
F(x
n
) → 0. This completes the proof.
Remark 3.3. It is clear that condition (C1)' is strictly weaker than condition (C1). In the meantime, condition (C5)' is also strictly weaker than condition (C5).
Corollary 3.4. (Yao et al. [5, Theorem 3.2]). Let H be a real Hilbert space. Let F : H → H be k-Lipschitzian and η-strongly monotone operator with k ∈ [1, ∞) and η ∈ (0, 1). Let
be an infinite family of nonexpansive mappings such that
and {W
n
} be W-mapping defined by (2.3). Let {λ
n
} be a sequence in [0, ∞) and {α
n
} be a sequence in [0,1]. Assume that
(C1) limn→1λ
n
= 0;
(C2)
;
(C5)
for some γ > 0.
Then, the sequence {x
n
} and {y
n
} generated by (1.2) converge strongly to
, which solves the following variational inequality 〈Fx*, x* - x〉 ≤ 0,
.
Proof. Since limn→∞λ
n
= 0, it is easy to see that
, ∀n ≥ n0 for some integer n0 ≥ 0. Without loss of generality, we assume that
, ∀n ≥ n0 for some integer n0 ≥ 0. Repeating the same argument as in the proof of Theorem 3.2, we know that {x
n
} is bounded, and so are the sequence {y
n
} and {F(x
n
)}. Therefore, we have λ
n
F(x
n
) → 0.
From
for some γ > 0, we have 0 < γ ≤ lim infn→∞α
n
≤ lim supn→∞α
n
< 1 for some γ ∈ (0, 1). Therefore, all conditions of Theorem 3.2 are satisfied. Hence, using Theorem 3.2, we have that {y
n
} converges strongly to
which solves the following variational inequality 〈Fx*, x* - x〉 ≤ 0,
. It follows from (3.17) that {x
n
} also converges strongly to
. This completes the proof.
Remark 3.5. Theorem 3.2 is more general than Theorem 3.2 of Yao et al. [5]. The following example shows that all conditions of Theorem 3.2 are satisfied. However, the conditions λ
n
→ 0, η ∈ (0, 1) and
for some γ > 0 in [5, Theorem 3.2] are not satisfied.
Example 3.6. Let H = R the set of real numbers and T
n
≡ T. Define a nonexpansive mapping T : H → H and an operator F : H → H as follows:
It is easy to see that F(T) = {0},
and W
n
x = (1 - ξ1)x, ∀x ∈ R. Let
, we have
, ∀x ∈ R. Given sequences {α
n
} and
,
for all n ≥ 0. For an arbitrary x0 ∈ H, let {x
n
} defined as follows:
that is,
Observe that for all n ≥ 0,
Hence, we have
for all n ≥ 0. This implies that {x
n
} converges strongly to
. Since
, we have that {y
n
} converges strongly to
.
Observe that 〈F(0), 0 - u〉 ≤ 0,
, that is, 0 is the solution of the variational inequality 〈Fx*, x* - u〉 ≤ 0,
.
Finally, we have
By F(x) = x, we have η = k = 1. Furthermore, it is easy to see that the following hold true:
(B1)
, ∀n ≥ n0 for some integer n0 ≥ 0;
(B2)
;
(B3)
for some constant
.
Hence, there is no doubt that all conditions of Theorem 3.2 are satisfied. Since
, η = 1 and
, the conditions that λ
n
→ 0,
for some γ > 0 and η ∈ (0, 1) of Yao et al. [5, Theorem 3.2] are not satisfied.
Next, we give a weak convergence theorem for hybrid iterative algorithm (1.2) involving an infinite family of nonexpansive mappings in a Hilbert space.
Theorem 3.7. Let H be a real Hilbert space. Let F : H → H be k-Lipschitzian and η-strongly monotone operator with 0 < η ≤ k. Let
be an infinite family of nonexpansive mappings such that
, and {W
n
} be W-mapping defined by (2.3). Let {λ
n
} and {α
n
} be two sequences in (0, 1). Assume that
(A1)
;
(A2) 0 < lim infn→∞α
n
≤ lim supn→∞α
n
< 1.
Then, the sequence {x
n
} and {y
n
} generated by (1.2) converge weakly to
.
Proof. From (A1), we have
, ∀n ≥ n0 for some integer n0 ≥ 0. Repeating the same argument as in the proof of Theorem 3.2, we know that {x
n
} is bounded, and so are the sequences {y
n
} and {F(x
n
)}. Assuming
, we have
where M4 = sup{||F(x
n
)||2, 2 ||x
n
- p|| ||F(x
n
)||, n ≥ 0}. Since
, we have
. Therefore,
. Utilizing Lemma 2.4, we deduce that limn→∞||x
n
- p|| exists. Further-more, from(3.17), we have
Since λ
n
→ 0,
and (A2), it follows from (3.18) that
Utilizing Lemma 2.6, we have
Now, we show that ω
w
(y
n
) ⊂ F(T). Indeed, let x* ∈ ω
w
(y
n
). Then, there exists a subsequence
of {y
n
} such that
. Since ||y
n
- Wy
n
|| → 0, by Lemma 2.1, we have
.
Next, we show that ω
w
(y
n
) is a singleton. Indeed, let
be another subsequence of {y
n
} such that
. Then,
. If
, then, by Opial's property of H, we have
This is a contradiction. Therefore, ω
w
(y
n
) is a singleton. Consequently, {y
n
} converges weakly to
. From (1.2), we have that {x
n
} converges weakly to
. This completes the proof.
Remark 3.8. It is worth pointing out that the conditions (C1) and (C2) in [5, Theorem 3.2] are replaced by the one (A1) in Theorem 3.7. It is also worth pointing out that condition (A2) is strictly weaker than the condition (C5). The advantages of there results in this study are that weaker and fewer restrictions are imposed on parameters α
n
, λ
n
and η.