Theorem 3.1 Let C be a nonempty, closed and convex subset of a real Hilbert space H, let be a countable family of uniformly closed and uniformly Lipschitz pseudocontractive mappings with Lipschitzian constants , let . Assume that the interior of is nonempty. Let be a sequence generated from an arbitrary by the following algorithm:
(3.1)
where satisfying the following conditions: (i) , ; (ii) ; (iii) with . Then converges strongly to .
Proof Suppose that . Then from (3.1) and Lemma 2.1, we have that
In addition, using (3.1), we have that
(3.5)
Substituting (3.4) and (3.5) into (3.3), we obtain that
(3.6)
Since
Then, substituting (3.8) into (3.7), we obtain that
(3.9)
Substituting (3.6) and (3.9) into (3.2), we obtain that
(3.10)
Since from condition (iii), we have that
Again from condition (i), we have that and . So, inequality (3.10) implies that
(3.11)
Then
(3.12)
It is obviously that exists, then is bounded. This implies that , , , , and are also bounded.
Furthermore, from (2.3), we have that
This implies that
(3.13)
Moreover, since the interior of F is nonempty, there exists and such that whenever . Thus, from the fact that , and (3.12) and (3.13), we get that
(3.14)
Then from (3.13) and (3.14), we obtain that
and hence
Since h with is arbitrary, we have
So, if , then we get that
But we know that converges. Therefore, we obtain that is a Cauchy sequence. Since C is closed subset of H, there exists such that
Furthermore, from (3.11) and conditions (i), (ii) and (iii), we get that
from which it follows that
(3.16)
Since are uniformly closed, then from (3.15) and (3.16), we obtain that . The proof is complete. □
Theorem 3.2 Let C be a nonempty, closed and convex subset of a real Hilbert space H, let be a finite family of uniformly closed and uniformly Lipschitz pseudocontractive mappings with Lipschitzian constants , . Assume that the interior of is nonempty. Let be a sequence generated from an arbitrary by the following algorithm:
(3.17)
where and satisfying the following conditions: (i) , ; (ii) ; (iii) with for . Then converges strongly to .
If in Theorem 3.1, we consider a single Lipschitz pseudocontractive mapping, then we may change the conditions of Theorem 3.1.
Theorem 3.3 Let C be a nonempty, closed and convex subset of a real Hilbert space H, let be a Lipschitz pseudocontractive mappings with Lipschitzian constants L. Assume that the interior of is nonempty. Let be a sequence generated from an arbitrary by the following algorithm:
(3.18)
where satisfying the following conditions: (i) , ; (ii) ; (iii) with . Then converges strongly to .
Proof Following the method of proof of Theorem 3.1, we obtain that .
Furthermore, from (3.10) and conditions (i) and (ii), we obtain (3.11). From (3.11) and conditions (iii) and (iv), we obtain that
from which it follows that
and hence there exists a subsequence of such that
Thus, and the continuity of T imply that , and hence . □