We start with some propositions which are common tools for proving the main results in the next two subsections.
Proposition 3.1 Let be a sequence of a complete space X such that . Suppose that exists for all . Then Δ-converges to an element of . Moreover, consists of exactly one point.
Proof Let x be the asymptotic center of and let be any subsequence of with the asymptotic center y. We show that and hence Δ-converges to x as desired. Since , there exists a subsequence of such that Δ-converges to z for some . Clearly, and it follows from the assumption that exists. Let . Then
Since
we have . Since
we have . This implies that . □
Proposition 3.2 Let X be a complete space and be a countable family of quasi-nonexpansive mappings with . Let be a sequence in X such that and
where is a sequence in . Then
-
(i)
is well defined and . In particular, and for all whenever and .
-
(ii)
If , then Δ-converges to an element of F.
Proof (i) Let be such that . Since , we have that . This implies that is well defined. It follows from Lemma 2.5 that
and we have
Therefore, . Using mathematical induction, we can conclude that the sequence is well defined and
Then exists which is less than , and so . This implies that .
(ii) Let . Then there exists a subsequence of such that Δ-converges to u. Notice that . Thus there is such that . Similar to the first step, we have that for all . This implies that exists. It follows immediately from Proposition 3.1 that Δ-converges to an element of F and the proof is finished. □
3.1 Countable nonexpansive mappings
The following concept is introduced by Aoyama et al. [13]. Let X be a complete metric space and be a countable family of mappings from X into itself with . We say that satisfies AKTT-condition if
-
for each bounded subset Y of X;
-
for all and .
Remark 3.3 Assume that satisfies AKTT-condition.
-
(1)
For each , we have is a Cauchy sequence and hence the mapping T above is well defined.
-
(2)
If is bounded, then .
Theorem 3.4 Let X be a complete space and be a countable family of mappings from X into itself. Let be a sequence in X defined by and
where is a sequence in . Suppose that
-
() is nonexpansive for all and ;
-
(C1) ;
-
(C2) ;
-
(C3′) satisfies AKTT-condition.
Then the sequence Δ-converges to a common fixed point of .
Proof We first show that exists. Using the nonexpansiveness of and the definition of , we obtain that
for all . It follows from Lemma 2.2 and that
exists.
Next, we show that . Assume that . Thus, without loss of generality, there is a positive real number A such that
To get the right inequality of the preceding expression, let be such that . By Proposition 3.2(i), we have
Put for all . By elementary trigonometry and Lemma 2.4, we get that
and it follows that
for all . Notice that , , and are positive. Consequently,
which is a contradiction. Then we get that and hence
where .
Finally, we show that Δ-converges to an element of . To apply Proposition 3.2(ii), we show that . Let . Then there exists a subsequence of such that Δ-converges to u. Clearly, u is the unique asymptotic center of . Using the nonexpansiveness of T and , we get that
This implies that , that is, . This completes the proof. □
As an immediate consequence of Theorem 3.4, we obtain the following result.
Corollary 3.5 Let X be a complete space and be a mapping. Let be the Mann algorithm (1.1) in X. Suppose that
Then the sequence Δ-converges to a fixed point of T.
Remark 3.6 Our Corollary 3.5 improves Theorem 3.1 of He et al. [6] (see Theorem 1.1) because (C1′) of Theorem 1.1 implies (C1) of Corollary 3.5. Moreover, (C1) is sharp in the sense that if , then we may construct the Mann algorithm for a nonexpansive mapping which is not Δ-convergent.
Example 3.7 Let be the unit sphere of the Euclidean space with the geodesic metric. Let be defined by
Then T is nonexpansive and . Let be a sequence in defined by and
Then and
It is easy to see that has the unique asymptotic center which is and has the unique asymptotic center which is . Hence, is not Δ-convergent.
3.2 Countable quasi-nonexpansive mappings
In this subsection, we give a supplement result to Theorem 3.4. Obviously, every nonexpansive mapping with a fixed point is quasi-nonexpansive. Moreover, if T is nonexpansive, then T is Δ-demiclosed [11], that is, if for any Δ-convergent sequence in X, its Δ-limit belongs to whenever .
In the following theorem, we deal with quasi-nonexpansive mappings satisfying Δ-demiclosedness. This interesting class of mappings includes the metric projections [11]. However, there are many metric projections such that they are not nonexpansive.
Theorem 3.8 Let X be a complete space and be a countable family of mappings from X into itself. Let be a sequence in X defined by and
where is a sequence in . Suppose that
-
(C0n) is quasi-nonexpansive for all and ;
-
(C1) ;
-
(C2′) ;
-
(C3) there exists a mapping such that
-
(C4) T is Δ-demiclosed.
Then the sequence Δ-converges to a common fixed point of .
Remark 3.9 Let us compare Theorems 3.4 and 3.8:
-
(1)
() ⇒ (C0n);
-
(2)
(C3′) ⇒ (C3);
-
(3)
(C0′) and (C3′) ⇒ (C4);
-
(4)
(C2′) ⇒ (C2).
Proof of Theorem 3.8 We first show that . Let be such that . We have that exists which is less than and by Proposition 3.2(i). Put . Notice that . Since , we may assume that there exists a subsequence of ℕ such that and . Using the quasi-nonexpansiveness of and Lemma 2.4, we get that
Letting yields
Using elementary trigonometry, we get that . Hence it follows that
By condition (C3), we get that
where .
Finally, we show that . Let . Then there exists a subsequence of such that Δ-converges to u. It follows from the Δ-demiclosedness of T and that , that is, . Hence the result follows from Proposition 3.2(ii). The proof is now finished. □
As an immediate consequence of Theorem 3.8, we obtain the following result.
Corollary 3.10 Let X be a complete space and be a mapping with . Let be the Mann algorithm (1.1) in X. Suppose that
Then the sequence Δ-converges to a fixed point of T.
Question 3.11 We do not know whether the conclusion of Corollary 3.10 holds if (C2′) is replaced by the more general condition (C2).
Let be a countable family of quasi-nonexpansive mappings with . We next show how to generate a family and a mapping W satisfying (C3′) and (C4), and hence Theorem 3.8 is applicable.
Theorem 3.12 Let X be a complete space such that for all , and let be a countable family of quasi-nonexpansive mappings with . Then there exist a family of quasi-nonexpansive mappings and a quasi-nonexpansive mapping such that
-
(i)
satisfies AKTT-condition and ;
-
(ii)
W is Δ-demiclosed whenever is Δ-demiclosed for all .
To prove Theorem 3.12, we need the following lemmas.
Lemma 3.13 ([14])
Let X be a complete space such that for all , and let be quasi-nonexpansive mappings with . Then, for each , and the mapping is quasi-nonexpansive.
The following lemma is essentially proved in [11]. For the sake of completeness, we show the proof.
Lemma 3.14 Let X be a complete space such that for all , and let be quasi-nonexpansive mappings with . Let be a sequence of X. If , then and .
Proof Put . By Lemma 3.13, we have that W is quasi-nonexpansive and . Let . By Lemma 2.4 and the quasi-nonexpansiveness of S and T, we get that
This implies that
It follows from that , that is, . Thus
Hence . Similarly, and the proof is finished. □
We are now ready to prove Theorem 3.12.
Proof of Theorem 3.12 Put for all . We define a family of mappings by
It follows from Lemma 3.13 that is quasi-nonexpansive for all and .
We first show that . For , put and
for all . By Lemma 2.3, we have that
for all and . Then
and the result follows. In particular, is a Cauchy sequence for each . We now define the mapping by
Next, we show that . It is easy to see that . On the other hand, let and . We prove that for all . Let be given. For any , it follows from Lemma 2.5 that
Letting yields and
This implies that . It follows from Lemma 2.4 that
Using elementary trigonometry, we get that . Since k is arbitrary, we have . Hence (i) is proved.
Finally, we prove (ii). We assume that is Δ-demiclosed for all . We show that W is Δ-demiclosed. Let be such that and Δ-converges to . It follows from the definitions of and that
Similar to the proof of the first and the second steps, we can define the quasi-nonexpansive mapping by
and . This implies that
Then, by Lemma 3.14, we obtain that and . Thus
Since is Δ-demiclosed, we have . Continuing this procedure gives . This completes the proof. □